If the equilibrium constant for N_(2) (g) + O_(2) (g) hArr 2 NO (g) " is " K, the equilibrium constant for 1/2 N_(2) (g) + 1/2 O_(2) (g) hArr NO (g) " will be "

If the equilibrium constant for N_(2) (g) + O_(2) (g) hArr 2 NO (g) "

1.	If the equilibrium constant for N_(2) (g) + O_(2) (g) hArr 2 NO (g) " is " K, the equilibrium constant for 1/2 N_(2) (g) + 1/2 O_(2) (g) hArr NO (g) " will be "
Answer» `1/2K` K `K^(2)` `K^(1//2)` Solution :When a REACTION is dividend by 2 , new equilibrium constant (K') is square root of the equilibrium constant (K) of the given reaction , i.e., new `K' = SQRT(K)= K^(1//2).`