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If the equilibrium constant for the given reaction is 0.25 `NOhArr(1)/(2)N_(2)+(1)/(2)O_(2)`, then the equilibrium constant for the reaction `(1)/(2)N_(2)+(1)/(2)O_(2)hArrNO` will beA. 1B. 2C. 3D. 4 |
Answer» Correct Answer - D `NOhArr(1)/(2)N_(2)+(1)/(2)O_(2),K_(c)=0.25` `(1)/(2)N_(2)+(1)/(2)O_(2)hArrNO,K_(c)=(1)/(0.25)=4` |
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