If the equilibrium constant for the reaction, H_(2)(g)+I_(2) Leftrightarrow 2HI(g) is K. What is the equilibrium constant of HI(g) Leftrightarrow 1/2 H_(2) (g)+1/2 I_(2) (g)?

If the equilibrium constant for the reaction, H_(2)(g)+I_(2) Leftright

1.	If the equilibrium constant for the reaction, H_(2)(g)+I_(2) Leftrightarrow 2HI(g) is K. What is the equilibrium constant of HI(g) Leftrightarrow 1/2 H_(2) (g)+1/2 I_(2) (g)?
Answer» Solution :`H_(2) (G)+I_(2) (g) LEFTRIGHTARROW 2HI(g), K` `K=([HI]^(2))/([H_(2)] [I_(2)]) .......(1)` For the REACTION, `HI(g) Leftrightarrow 1/2 H_(2) (g)+1/2 I_(2) (g)` equilibrium CONSTANT. `K.=([H_(2)]^(1//2) [I_(2)]^(1//2))/([HI]) ""K.=(1)/(K^(1//2))=(1)/sqrtK`