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If the equlibrium constant for the reaction of weak acid HA with strong base is 10^(9) then calculate the pH of 0.1 M NaA. |
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Answer» ` K_a =(K_W)/( K_h)= 10 ^(-5) rArr PH =7 +(P^(K_a))/( 2) + (1)/(2) LOG C ` ` =7 +(5)/(2) +(1)/(2) log 10 ^(-1)= 9` |
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