1.

If the equlibrium constant for the reaction of weak acid HA with strong base is 10^(9) then calculate the pH of 0.1 M NaA.

Answer»


SOLUTION :`K_n =10 ^(9), K_h =(1)/( K_n)= 10 ^(9) `
` K_a =(K_W)/( K_h)= 10 ^(-5) rArr PH =7 +(P^(K_a))/( 2) + (1)/(2) LOG C `
` =7 +(5)/(2) +(1)/(2) log 10 ^(-1)= 9`


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