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If the error in the measurement of momentum of a particle is (+ 100%), then the error in the measurement of kinetic energy isA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - C Since error in measurement of momentum is +100%.`p_(1)=p,p_(2)=2p` `K_(1)=(p^(2))/(2m),K_(2)=((2p)^(2))/(2m)` `%"in" K=((K_(2)-K_(1))/(K_(1)))xx100` `=((4-1)/(1))xx100=300%` |
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