If the error in the measurement of radius is 2%, then the error in the determination of volume of the pshere will be

If the error in the measurement of radius is 2%, then the error in the

1.	If the error in the measurement of radius is 2%, then the error in the determination of volume of the pshere will be
Answer» `8%` `2%` `4%` `6%` Solution :Volume of the sphere, V `= 4/3 pir^(3)` `(DELTAV)/(V) XX 100= 3 xx ((Deltar)/(R)xx100) = 3 xx 2%` `(DeltaV)/(v) xx 100 = 6%`