1.

If the expansion of 1(1−ax)(1−bx)=a0+a1x+a2x2+⋯+anxn+⋯, then an is (where a≠b,|ax|,|bx|<1)

Answer»

If the expansion of 1(1ax)(1bx)=a0+a1x+a2x2++anxn+, then an is (where ab,|ax|,|bx|<1)



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