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If the expression `ax^3+2x^2y-bxy^2-2y^3` is symmetric, then `(a,b)` = |
Answer» `x=y` `ax^3+2x^2y-bxy^2-2y^2=ay^3+2y^2x-byx^2-2x^3` `ax^3+2x^2y-bxy^2-2y^3=-2x^3-bx^2y+2y^2x+ay^3` `a=-2` `b=-2` `(a,b)=(-2,-2)`. |
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