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If the expression (px3 + x2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ?(a) 2, – 1 (b) –2, 1 (c) –2, –1 (d) 2, 1 |
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Answer» (d) 2, 1 px3 + x2 – 2x – q is divisible by (x – 1) and (x + 1) ⇒ p(1)3 + (1)2 – 2(1) – q = 0 ⇒ p – q = 1 ...(i) and p(–1)3 + (–1)2 – 2(–1) – q = 0 ⇒ p + q = 3 ...(ii) Solving (i) and (ii) p = 2, q = 1. |
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