1.

If the expression (px3 + x2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ?(a) 2, – 1 (b) –2, 1 (c) –2, –1 (d) 2, 1

Answer»

(d) 2, 1

px3 + x2 – 2x – q is divisible by (x – 1) and (x + 1) 

⇒ p(1)3 + (1)2 – 2(1) – q = 0 ⇒ p – q = 1               ...(i) 

and p(–1)3 + (–1)2 – 2(–1) – q = 0 ⇒ p + q = 3        ...(ii) 

Solving (i) and (ii) p = 2, q = 1.



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