If the [F^-] = 2.0 xx 10^(-5) M in water. Then, how many gram of CaCl_2 will be added for precipitation of F^-? K_(sp) for CaF_2 = 1.7 xx 10^(-10). (Molecular mass of CaCl_2 = 111 "g mol"^(-1))

If the [F^-] = 2.0 xx 10^(-5) M in water. Then, how many gram of CaCl_

1.	If the [F^-] = 2.0 xx 10^(-5) M in water. Then, how many gram of CaCl_2 will be added for precipitation of F^-? K_(sp) for CaF_2 = 1.7 xx 10^(-10). (Molecular mass of CaCl_2 = 111 "g mol"^(-1))
Answer» SOLUTION :More than 47.175 GM of `CaCl_2`is to be ADDED