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If the first term of an AP is -5 and the common difference is 2, then the sum of the first 6 terms is |
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Answer» Correct Answer - A Here `a=-5, d=2, n=6` `:. S_(n)=(n)/(2)[2a+(n-1)d]` `rArr S_(6)=(6)/(2)[(2(-5)+(6-1)(2)]=3(-10+10)=0` |
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