If the five-digit number 136xy is divisible by 3, 7, and 11, then, wha

1.	If the five-digit number 136xy is divisible by 3, 7, and 11, then, what is the value of x2 + y2 + (5y/3)?1. 902. 1003. 854. 110
Answer» Correct Answer - Option 2 : 100 GIVEN The five-digit number 136xy is divisible by 3, 7, and 11. CALCULATION: Firstly, we evaluate the LCM of (3, 7 and 11) = 3 × 7 × 11 = 231 The largest possible value of 136xy is 13699. When we divide 13699 by 231, we obtain 70 as the remainder. So, required number = 13699 – 70 = 13629 ∴ x = 2 and y = 9 According to question – ⇒ x² + y² + 5y/3 = 2² + 9² + 5(9)/3 ⇒ 4 + 81 + 15 ⇒ 100 ∴ The correct answer is 100.

If the five-digit number 136xy is divisible by 3, 7, and 11, then, what is the value of x2 + y2 + (5y/3)?1. 902. 1003. 854. 110

Answer» Correct Answer - Option 2 : 100

GIVEN

The five-digit number 136xy is divisible by 3, 7, and 11.

CALCULATION:

Firstly, we evaluate the LCM of (3, 7 and 11) = 3 × 7 × 11 = 231

The largest possible value of 136xy is 13699.

When we divide 13699 by 231, we obtain 70 as the remainder.

So, required number = 13699 – 70 = 13629

∴ x = 2 and y = 9

According to question –

⇒ x² + y² + 5y/3 = 2² + 9² + 5(9)/3

⇒ 4 + 81 + 15

⇒ 100

∴ The correct answer is 100.

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If the five-digit number 136xy is divisible by 3, 7, and 11, then, what is the value of x2 + y2 + (5y/3)?1. 902. 1003. 854. 110

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