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If the flux linkage in coil 1 is 3Wb and it has 500 turns and the current in coil 2 is 2A, calculate the mutual inductance.(a) 750H(b) 500H(c) 450H(d) 900H |
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Answer» Right option is (a) 750H The best I can explain: We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil. M=3*500/2=750H. |
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