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If the focal length of a magnifier is 5cm calculate (a) the power of the lens (b) the magnifying power of the lens for relaxed and strained eye. |
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Answer» Solution :(a) As POWER of a LENS is RECIPROCAL of FOCAL length in m. `P=1/(( 5 TIMES 10^-2 m))=1/0.0` diopter =20D (b) For relaxed eye, MP is minimum and will be `MP=D/f=25/5=5` While for strained eye, MP is maximum and will be `MP=1+D/f=1+5=6` |
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