1.

If the foci of a hyperbola lie on `y=x`and one of the asymptotes is `y=2x ,`then the equation of the hyperbola, given that it passes through (3,4), is`x^2-y^2-5/2x y+5=0``2x^2-2y^2+5x y+5=0``2x^2+2y^2+5x y+10=0`none of these

Answer» Correct Answer - `2x^(2)+2y^(2)-5xy+10=0`
The foci of the hyperbola lie on y = x. So, the major axis is y = x.
The major axis of hyperbola bisects the asymptote.
Therefore, the equation of other asymptote is x = 2y.
Thus, the equation of hyperbola is `(y-2x)(x-2y)+k=0.`
Given that it passes through (3,4), we get `k=-10.`
Hence, the required equation is
`2x^(2)+2y^(2)-5xy+10=0`


Discussion

No Comment Found

Related InterviewSolutions