1.

If the force is proportional to square of velocity, the the dimensional of proportionality constant is

Answer»

`MLT^(0)`
`ML^(-1)T^(0)`
`MLT^(-1)`
`ML^(-2)T`

SOLUTION :`FpropV^(2)impliesF=KV^(2)impliesK=(F)/(V^(2))`
dimensionally, `K=(MLT^(-2))/(L^(2)T^(-2))=[ML^(-1)T^(0)]`.


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