Related InterviewSolutions

• Among two interfering sources, let `S_1` be ahead of the phase by `90^@` relative to `S_2` . If an observation point P is such that `PS_1 - PS_2 = 1.5 lambda` , the phase difference between the waves from `S_1 and S_2` reaching P isA. `3pi`B. `(5pi)/2`C. `(7pi)/2`D. `4pi`
• A string that is 10 cm long is fixed at both ends. At t=0, a pulse travelling from left to right at `1cm//s is 4.0 cm ` from the right end as shown in figure. Determine the next two times when the pulse will be at that point again. State in each case whether the pulse is upright or inverted . .
• A man generates a symmetrical pulse in a string by moving his hand up and down. At `t=0` the point in his hand moves downward. The pulse travels with speed of `3 m//s` on the string & his hands passes `6` times in each second from the mean position. Then the point on the string at a distance `3m` will reach its upper extreme first time at time `t=`A. 1.25 sB. 1sC. `11//12 s `D. 23/24 s
• A standing wave is formed by two harmonic waves, `y_1 = A sin (kx-omegat) and y_2 = A sin (kx + omegat)` travelling on a string in opposite directions. Mass density energy between two adjavent nodes on the string.
• `y_1 = 8 sin (omegat - kx) and y_2 = 6 sin (omegat + kx)` are two waves travelling in a string of area of cross-section s and density rho. These two waves are superimposed to produce a standing wave. (a) Find the energy of the standing wave between two consecutive nodes. (b) Find the total amount of energy crossing through a node per second.
• A wave travels on a light string. The equation of the waves is `y= A sin (kx - omegat + 30^@)`. It is reflected from a heavy string tied to an end of the light string at x = 0. If 64% of the incident energy is reflected, then the equation of the reflected wave isA. `y = 0.8 A sin (kx - omegat + 30^@ + 180^@)`B. `y = 0.8 A sin (kx + omegat + 30^@ + 180^@)`C. `y= 0.8 A sin (kx - omegat - 30^@)`D. `y= 0.8 A sin (kx - omegat + 30^@)`
• Which of the following equations can form stationary waves? (i)`y= A sin (omegat - kx)` (ii) `y= A cos (omegat - kx)` (iii) `y= A sin (omegat + kx)` (iv) `y= A cos (omegat - kx)` .A. (i) and (ii)B. (i) and (iii)C. (iii) and (iv)D. (ii) and (iv)
• Regarding stationary waves, choose the correct options.A. This is an example of interferenceB. Amplitudes of waves may be differentC. particles at nodes are always at restD. Energy is conserved
• Incident wave `y= A sin (ax + bt+ pi/2)` is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by `y= -1.6 sin ax sin bt + cA cos (bt + ax)` where A, a, b and c are positive constants. 3. Position of second antinode isA. `x = pi/(3a)`B. `x = (3pi)/a`C. `x = (3pi)/(2a)`D. `x = (2pi)/(3a)`
• Assertion: Stationary waves are so called because particles are at rest in stationary waves. Reason: They are formed by the superposition of two identical waves travelling in opposite directions.A. If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.B. If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.C. If Assertion is true, but the Reason is false.D. If Assertion is false but the Reason is true.