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If the function f(x)={2a2x−1;x≤1x2+x+b;x>1 is differentiable everywhere, where a,b∈R, then the value of 2a2+b is

Answer» If the function f(x)={2a2x−1;x≤1x2+x+b;x>1
is differentiable everywhere, where a,b∈R, then the value of 2a2+b is


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