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If the function f(x)=ax3+bx2+11x−6,a,b∈R satisfies Rolle's theorem in [1,3] and f′(2+1√3)=0, then the value of (a−b) is |
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Answer» If the function f(x)=ax3+bx2+11x−6,a,b∈R satisfies Rolle's theorem in [1,3] and f′(2+1√3)=0, then the value of (a−b) is |
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