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If the function f(x) & g(x) are defined on R to R such that f (x) = {{:( 0 , x in "rational") , (x "," , x in "irrational"):} g(x) = {{:( 0 "," , x in "irrational" ) , ( x "," , x in "rational" ):} then (f-g) (x) is |
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Answer» ONE-one and onto |
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