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If the function f(x)=sin^(-1)x+cos^(-1)x and g(x) are identical, then g(x) can be equal to |
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Answer» `sin^(-1)|x|+|cos^(-1)x|` If `g(x)=|sin^(-1)x|+cos^(-1)|x|={{:(-sin^(-1)x +pi-cos^(-1)x, -1le x lt 0),(=pi-(pi)/(2)=(pi)/(2)),(sin^(-1)x + cos^(-1)x, 0LE x le 1),(=(pi)/(2)):}` |
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