1.

If the function x=cos^(2)omegat+bsin^(2)omegat+csinomegatcosomegat represent a simple harmonic motion , then which of the foloowing options can be possible ?

Answer»

a=-b,c=2a
a=b,c=-2b
a=b=0,c `ne`0
a=b,c=0

Solution :`x = a cos^(2) omegat + b sin^(2) omegat + c sin omegat cos omegat`
`= a((1 + cos 2omegat)/(2)) + b((1-cos 2omegat)/(2)) + (1)/(2) c sin 2omegat`
(a) : For `a = -b and c= 2a`
`x = a cos^(2)omegat - a sin^(2)omegat + 2 a sin omegat cos omegat`
` = a(cos^(2)omegat _ sin^(2)omegat) + a SIN2 omegat`
` = a cos 2omegat + a sin 2omegat`
` = sqrt(2) a sin (2omegat + (PI)/(4))`
This represents S.H.M. option (a) is true.
(b) : `a= b , c --2b`
` x = b cos^(2)omegat + b sin^(2) omegat - 2b sin omegat cos omegat`
` = b-bsin 2omegat`
` = b(1-sin 2omegat)`
` = b(1-sin2omegat)`
This represents S.H.M. of amplitude b. But EQUILIBRIUM occurs at b instead of zero. Option (b) is also true.
(c ) a = b = c and `c ne 0`
For a = b = 0 `x = (c)/(2) sin2omegat`
This represents S.H.M. of option (b) is also true.
(d) : a = b and c = 0
`therefore x = b cos^(2)omegat + b sin^(2) omegat = b`
This does not represent S.H.M.


Discussion

No Comment Found