If the gravitational force between two objects were proportional to 1/R(and not as 1/R^2 ) where R is the distance between them, then a particle in a circular path (under such a force) would have its orbital speed v_1proportional to .........

If the gravitational force between two objects were proportional to 1/

1.	If the gravitational force between two objects were proportional to 1/R(and not as 1/R^2 ) where R is the distance between them, then a particle in a circular path (under such a force) would have its orbital speed v_1proportional to .........
Answer» `1/R^2` `R^@` `R^1` `1/R` SOLUTION :`implies (mv^2)/R = (K)/R (FPROP 1/R)` `:. V PROP R^@`