If the half-cell reaction ` A = E^(-) rarr A^-` has a large negative reduction potential, it follows that .A. A is readily oxidisedB. A is readily reducedC. `A^(-)` is readily oxidisedD. `A^(-)` is readily reduced.

If the half-cell reaction ` A = E^(-) rarr A^-` has a large negative r

1.	If the half-cell reaction ` A = E^(-) rarr A^-` has a large negative reduction potential, it follows that .A. A is readily oxidisedB. A is readily reducedC. `A^(-)` is readily oxidisedD. `A^(-)` is readily reduced.
Answer» Correct Answer - C (c ) `A^(-)` ion is readily oxidised to A by losing an electron.

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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

If the half-cell reaction ` A = E^(-) rarr A^-` has a large negative reduction potential, it follows that .A. A is readily oxidisedB. A is readily reducedC. `A^(-)` is readily oxidisedD. `A^(-)` is readily reduced.

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