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If the half cell reactions ae given as (i)Fe^(2+)(aq)+2e^(-) rarrFe(s),E^(@)=-0.44 V (ii)23H^(+) (aq)+1//2O_(2)(g)+2e^(-)rarrH_(2)O(l),E^(@)=+1.23V The E^(@) for the reaction Fe(s)+2H^(+)(aq)+1//2 O_(2) (g) rarr Fe^(2+) (aq)+H_(2)O (l) is |
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Answer» `1.67 V` |
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