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If the heat fo dissolution of anhydrous `CuSO_(4)` and `CuSO_(4).5H_(2)O` is `-15.89 kcal` and `2.80 kcal`, respectively, then the heat of hydration of `CuSO_(4)` to form `CuSO_(4).5H_(2)O` isA. `-13.09` kcalB. `-18.69` kcalC. `+13.09`kcalD. `+18.69` kcal |
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Answer» Correct Answer - B (i) `CuSO_4+aqto CuSO_4(ag)DeltaH_1=-1589kcal` (ii) `CuSO_4.5H_2O+aqtoCuSO_4(aq)DeltaH_2=+2.8kcal` Eq.(i) -Eq.(ii) gives `DeltaH=-1869kcal (DeltaH=DeltaH_1-DeltaH_2)` |
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