. If the highest common factor of numbers 408and 1032 is expressed in

1.	. If the highest common factor of numbers 408and 1032 is expressed in the form of 1032x408 x 5, then find the value of x.
Answer» If the HCF of 408 and 1032 can be written as By Euclid 's division algorithm, 1032 = 408×2 + 216 408 = 216×1 + 192 216 = 192×1 + 24 192 = 24×8 + 0 Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24 Now, 1032x - 408*5 = HCF of these numbers => 1032x - 2040 = 24 => 1032x = 24+2040 => x = 2064/1032 => x = 2 So value of x is 2. Like my answer if you find it useful!

. If the highest common factor of numbers 408and 1032 is expressed in the form of 1032x408 x 5, then find the value of x.

Answer»

If the HCF of 408 and 1032 can be written as

By Euclid 's division algorithm,

1032 = 408×2 + 216

408 = 216×1 + 192

216 = 192×1 + 24

192 = 24×8 + 0

Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24

Now,

1032x - 408*5 = HCF of these numbers

=> 1032x - 2040 = 24

=> 1032x = 24+2040

=> x = 2064/1032

=> x = 2

So value of x is 2.

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