If the inclination of an inclined plane is 30^(@), a block of mass m kept at rest on the surface of the plane, will just slide down. If the inclination is raised to 45^(@) what will be the acceleration of the body ?

If the inclination of an inclined plane is 30^(@), a block of mass m k

1.	If the inclination of an inclined plane is 30^(@), a block of mass m kept at rest on the surface of the plane, will just slide down. If the inclination is raised to 45^(@) what will be the acceleration of the body ?
Answer» Solution :when `theta=30^(@)`, the block just SLIDES down So `mu=tantheta=tan30^(@)=0.5774` The ACCELERATION of a BODY moving down the surface of an INCLINED plane is `a=g(sintheta-mucostheta)` `=9.8(sin45-0.5774cos45)` `a=2.93m//s^(2)`