If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is :

If the inertial mass and gravitational mass of the simple pendulum of

1.	If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is :
Answer» `T= 2PI sqrt((m_(i)l)/(m_(g)g))` `T= 2pi sqrt((m_(g)l)/(m_(i)g))` `T=2pi (m_(g))/(m_(i)) sqrt((l)/(g))` `T=2pi (m_(i))/(m_(g)) sqrt((l)/(g))` SOLUTION :`T= 2pi sqrt((M)/(K))` `:. T_(1)=2pi sqrt((M_(1))/(k)): T_(2)= 2pi sqrt((M_(2))/(k))` INERTIAL mass `M_(1) prop m_(i) l` Gravitational mass `M_(2) prop m_(g)g` `:. (T_(1))/(T_(2))= 2pi sqrt((M_(2)l)/(k))xx(1)/(2pi) sqrt((k)/(m_(g)g))` `:. T= 2pi sqrt((m_(i)l)/(m_(g)g)`