1.

If the ionisation constant of acetic acid is `1.8 xx 10^(-5)`, at what concentration will it be dissociated to `2%`?A. `1M`B. `0.018M`C. `0.18M`D. `0.045M`

Answer» Correct Answer - D
`{:(,CH_(3)COOHhArr,CH_(3)COO^(-),H^(+)),("initially ",C,0,0),("At equilibrium",C(1-a),Calpha,Calpha):}`
`K = (Calpha. Calpha)/(C(1-alpha)) = (Calpha^(2))/(1-alpha) = Calpha^(2)`
or `C = (K)/(alpha^(2)) = (1.8 xx 10^(-5))/((0.02)^(2)) = 0.045M`


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