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If the joining the points (0,3) and (5,-2) is a tangent to the curve `y=(c)/(X+1),` then value of c is -A. 1B. -2C. 4D. -4 |
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Answer» Correct Answer - 3 Equation of the line joining given points is `(y+2)=(-2-3)/(5-0)(x-5)` `rArry+2=-1(x-5)` `rArry+x=3` Solving with the curve `y=(c)/(x+1),` we get `(3-x)(x+1)=c` `rArrx^(2)-2x+c-3=0` For equal roots `4-4(c-3)=0rArrc=4` |
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