If the kinetic energy of a particle is doubled, by what factor the de Broglie wavelength of the particle increase or decrease ?

If the kinetic energy of a particle is doubled, by what factor the de

1.	If the kinetic energy of a particle is doubled, by what factor the de Broglie wavelength of the particle increase or decrease ?
Answer» Solution :`lamda = (H)/(SQRT(2 E m))` where E = kinetic energy of the particle `:. (lamda_(1))/(lamda_(2)) = sqrt2 or lamda_(2) = (lamda_(1))/(sqrt2) = (1)/(1.414) lamda_(1) = 0.7 xx lamda_(1)` Hence, de Broglic wavelength will DECREASE to 0.7 of its original value