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If the kinetic energy of an electron is 4.55 xx 10^(-25)J, find its wavelength (Planck's cosntant, h = 6.625 xx 10^(-34) kgm^(2)s^(-1), m = 9.1 xx 10^(-31)kg). |
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Answer» Solution :`"KE of ELECTRON, "1//2mv^(2)=4.55xx10^(-25)J`. `"Mass of electron, m"=9.1xx10^(-31)KG` `V^(2)=(2xxKE)/(m)=(2xx4.55xx10^(-25)J)/(9.1xx10^(-31)kg)RARR v^(2)=10^(6)m^(2)s^(-2)` `"Velocity of electron, v"=SQRT(10^(6))=10^(3)ms^(-1)` `therefore"Wave length, "lambda=(6.625xx10^(-34)Lgm^(2)s^(-1))/(9.1xx10^(-31)kgxx10^(3)ms^(-1))` `therefore"Wave length of electron "=lambda=728nm.` |
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