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If the kinetic energy of the body is increased by 300 % then , theincrease in momentum will be …… |
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Answer» 1 When kinetic energy increases300 % then Now kinetic energy `E_(2)=E+ 2E = 4E` Now `E = (p^(2))/(2m)` ` :. P prop sqrt€ ` (m = constant) `:. (p_(2))/(p_(1))=sqrt((E_(2))/(E_(1)))=sqrt((4E)/E)` ` :. p_(2) =2p_(1) =p_(1)+p_(1)` ` :. ` Momentum increased by 100 % |
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