1.

If the law of gravitation, instead of being inverse square law, becomes an inverse cube law

Answer»

planets will not have elliptic orbits 
circular orbits of planets is not possible 
projectile motion of a stone thrown by HAND on the SURFACE of the earth will beapproximately parabolic 
there will be no gravitational force INSIDE asspherical shell of uniform density

Solution :`implies` Gravitational force = CENTRIPETAL force,
`F = (GMm)/r^2 = (m^2)/r`
`:.` v = orbtial speed `=sqrt(GM)/r implies v prop 1/r`
Time period of revolution of planet,
`T= (2pir)/v = (2pir)/((sqrtGM)/r) = (2pir^2)/(sqrt(GM))`
`T^(2) prop r^4`
Hence, orbit will not be ELLIPTICAL. [for elliptical orbit `T_2 prop r^3` ]
As force `F = ((GM)/r^2) m = gm `
where `g. = (GM)/r^2`
As g., acceleration due to gravity is constant, hence path followed by a projectile will be approximately parabolic.


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