If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +- 0.001)cm and mass m = (6.25+- 0.01)g . Calculate the percentage error in determination of density.

If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +

1.	If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +- 0.001)cm and mass m = (6.25+- 0.01)g . Calculate the percentage error in determination of density.
Answer» SOLUTION :Density of cylinder, `rho=(("MASS")/("volume")V)=(m)/(pir^(2)L) ( :. V=pi r^(2)l)` `:.` Relative ERROR in `rho=(Delta rho)/(rho)=(Deltam)/(M)+2(Deltar)/(r)+(Deltal)/(l)` `=(0.01)/(6.25)+2xx(0.001)/(0.250)+(0.01)/(4.00)` `=0.0016+0.008+0.0025` `=:.(Delta rho)/(rho)=0.0121` `:.` The percentage error in `rho=0.0121xx100=1.2%`