If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +- 0.001)cm and mass m = (6.25+- 0.01)g . Calculate the percentage error in determination of density.

If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +

1.	If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +- 0.001)cm and mass m = (6.25+- 0.01)g . Calculate the percentage error in determination of density.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Density of cylinder, `rho=(("<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/("volume")V)=(m)/(pir^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>) ( :. V=pi r^(2)l)` <br/> `:.` Relative <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> in `rho=(Delta rho)/(rho)=(Deltam)/(M)+2(Deltar)/(r)+(Deltal)/(l)` <br/> `=(0.01)/(6.25)+2xx(0.001)/(0.250)+(0.01)/(4.00)` <br/> `=0.0016+0.008+0.0025` <br/> `=:.(Delta rho)/(rho)=0.0121` <br/> `:.` The percentage error in `rho=0.0121xx100=1.2%`</body></html>