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If the length of a rectangle is 14cm and its perimeter is 3 times of its length. Find its area. |
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Answer» Given the length of a rectangle l = 14 cm Breadth of a rectangle b = ? cm Perimeter of the rectangle = 2(l + b) = 3 times of length. 2(14 + b) = 3 x 14 Divide with 2 on both sides, \(\frac{2(14+b)}{2}=\frac{3\times14}{2}\) 14 + b = 21 Subtract with 14 on both sides. 14 + b – 14 = 21 – 14 Breadth b = 7cm Area of the rectangle A = l x b = 14 x 7 = 98 sq.cm |
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