1.

If the length of a rectangle is 14cm and its perimeter is 3 times of its length. Find its area.

Answer»

Given the length of a rectangle l = 14 cm 

Breadth of a rectangle b = ? cm 

Perimeter of the rectangle = 2(l + b) = 3 times of length. 

2(14 + b) = 3 x 14 

Divide with 2 on both sides,

\(\frac{2(14+b)}{2}=\frac{3\times14}{2}\)

14 + b = 21

Subtract with 14 on both sides.

14 + b – 14 = 21 – 14

Breadth b = 7cm

Area of the rectangle A = l x b = 14 x 7 = 98 sq.cm



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