If the length of diagnal of a cube is 8√3 cm then its surface area i

1.	If the length of diagnal of a cube is 8√3 cm then its surface area is (a) 192 cm2 (b) 384 cm2 (c) 512 cm2 (d) 768 cm2
Answer» If the length of diagnal of a cube is $8 \sqrt{3} c m$ then its surface area is $(a) 192 c m^{2} (b) 384 c m^{2} (c) 512 c m^{2} (d) 768 c m^{2}$

If the length of diagnal of a cube is 8√3 cm then its surface area is (a) 192 cm2 (b) 384 cm2 (c) 512 cm2 (d) 768 cm2

Answer»

If the length of diagnal of a cube is $8 \sqrt{3} c m$ then its surface area is

$(a) 192 c m^{2} (b) 384 c m^{2} (c) 512 c m^{2} (d) 768 c m^{2}$