1.

If the length of seconds pendulum is decreased by 1%, the gain or lose time per day by the pendulum will beA. gain 432 sB. lose 443 sC. gain 4.4 sD. lose 0.44 s

Answer» Correct Answer - A
`l_(2)=(l_(1)-0.01)`
`T_(1)=2pisqrt((l)/(g))andT_(2)=2pisqrt((0.99)/(g))`
`(T_(2))/(T_(1))=sqrt((0.99)/(1))`
`therefore T_(2)=2sqrt(99xx10^(-2))=2xx9.95xx10^(-1)`
`T_(2)=1.990s`
In 1 osci. Gain of time is, `2-1.990=0.01` s
`therefore` In one day i.e. 43200 oscillations
The time gain is 43200 `xx` 0.01 = 432


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