If the length of the body for `CaCl` which crystallizes into a cubic strructure with `Cl^(Θ)` ions at the corners and `Cs^(o+)` ions at the centre of the unit cell is `7 Å` and the radius of he `Cs^(o+)` ions is `1.69Å`, what is the radius of `Cl^(ɵ)` ions?

If the length of the body for `CaCl` which crystallizes into a cubic s

1.	If the length of the body for `CaCl` which crystallizes into a cubic strructure with `Cl^(Θ)` ions at the corners and `Cs^(o+)` ions at the centre of the unit cell is `7 Å` and the radius of he `Cs^(o+)` ions is `1.69Å`, what is the radius of `Cl^(ɵ)` ions?
Answer» Length of the body diagonal `= 2(r_(Cl^(Θ)) + r_(Cs^(o+)))`

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If the length of the body for `CaCl` which crystallizes into a cubic strructure with `Cl^(Θ)` ions at the corners and `Cs^(o+)` ions at the centre of the unit cell is `7 Å` and the radius of he `Cs^(o+)` ions is `1.69Å`, what is the radius of `Cl^(ɵ)` ions?

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