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If the length of the tangent from (2, 5) to the circle x2 + y2 – 5x + 4y + k = 0 is √37 then find k. |
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Answer» Length of tangent = √S11 = √((2)2 + (5)2 - 5 x 2 + 4 x 5 + k) = 37 = 39 + k = – 2 units. |
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