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If the length of the tangents from (a,b) to the circles x2+y2−4x−5=0 and x2+y2+6x−2y+6=0 are equal then 10a−2b is equal to |
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Answer» If the length of the tangents from (a,b) to the circles x2+y2−4x−5=0 and x2+y2+6x−2y+6=0 are equal then 10a−2b is equal to |
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