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If the line px + qy =1 is a tangent to the parabola `y^(2)` =4ax, thenA. `p^(2)-aq=0`B. `p+aq^(2)=0`C. `p-aq^(2)=0`D. `p-2aq^(2)=0` |
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Answer» Correct Answer - 2 `px+qy-1=0` `qy=px+1` `y=(-p)/(q)x+1/q` `Y^(2)=4ax` C.T `c=a//m` `1/q=a//-p//q` `p=-aq^(2)` `p+aq^(2)=0` |
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