1.

If the line's (1+t)x−2ty+3t2=0 and t2x−(3−t)y+6=0, t≠0 are perpendicular to each other, then the number of possible value(s) of t is

Answer»

If the line's (1+t)x2ty+3t2=0 and t2x(3t)y+6=0, t0 are perpendicular to each other, then the number of possible value(s) of t is



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