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If the line segment joining the points A(7, p, 2) and B(q, -2, 5) be parallel to the line segment joining the points C(2, -3, 5) and D(-6, -15,11), find the values of p and q. |
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Answer» Given: A(7, p, 2) and B(q, -2, 5), line segment joining these two points will be, AB = (q-7)i + (-2-p)j + 3k And the line segment joining C(2, -3, 5) and D(-6, -15, 11) will be, CD = -8i – 12j + 6k Then, the angle between these two line segments will be 0 degree. So, the cross product will be 0. AB x CD = 0 ((q-7)i + (-2-p)j + 3k) x ( -8i – 12j + 6k) = 0 Thus, solving this we get, p = 4 and q = 3 |
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