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If the line (x)/(1)=(y)/(2)=(z)/(3) intersects the line 3beta^2x+3(1-2alpha)y+z=3=-(1)/(2){(6alpha^2x+3(1-2beta)y+2z)} then point (alpha, beta, 1) lie on the plane |
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Answer» `2x-y+z=4` |
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