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If the line `x= alpha ` divides the area of region `R={(x,y)in R^(2): x^(3) le y le x ,0 le x le 1 } ` into two equal parts, thenA. ` 2 alpha^(4)-4alpha^(2)+1=0`B. `alpha^(4)+4alpha^(2)-1=0`C. `(1)/(2) lt alpha lt 1 `D. `0 lt alpha le (1)/(2)` |
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Answer» Correct Answer - A::C ` int_(0)^(1)(x-x^(3))dx= 2int_(0)^(alpha)(x-x^(3))dx ` `(1)/(4)=2((alpha^(2))/(2)-(alpha^(4))/(4))` `2 alpha^(4)-4 alpha^(2)+1=0 ` ` rArr alpha^(2)=(4-sqrt(16-8))/(4) " "( because alpha in (0,1))` ` alpha^(2)=1-(1)/(sqrt(2))` |
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