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If the line `y=2x+lambda` be a tangent to the hyperbola `36x^(2)-25y^(2)=3600`, then `lambda` is equal toA. `16`B. `-16`C. `+-16`D. none of these |
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Answer» The equation of the hyperbola is `(x^(2))/(100)-(y^(2))/(144)=1`. The line `y=2x+lambda` touches this hyperbola , if `lambda^(2)=100xx2^(2)-144` [Using `c^(2)=a^(2)m^(2)-b^(2)`] `implieslambda^(2)=256implieslambda`+-16` |
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