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If the linear momentum is increased by 50%, then KE will be increased by :A. 0.5B. 1C. 1.25D. 0.25 |
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Answer» Correct Answer - C Let `p_(1) = p, p_(2)=p_(1)+50%` of `p_(1)=p_(1) + p_(t)/2 = (3p_(1)/(2)` `E alpha p^(2)` `rArr E_(2)/E_(1) = (p_(2)/p_(1))^(2) = ((3p_(1)//2)/p_(1))^(2) = 9/4` `rArr E_(2) = 2.25E_(1) = E_(1) + 1.25E_(1)` `therefore E_(2) = E_(1) + 125% of E_(1)` i.e., Kinetic energy will increase by 125%. |
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