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If the linear momentum is increased by 50%, then kinetic energy will be increased by |
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Answer» 50% where p is the momentum of the body and m is the mass of the body. `p. = p + (50)/(100) p = 3/2 p` Assuming m remains constant `:. (K^.)/(K) = ((P.)/(P))^(2) = 9/4` % INCREASE in kinetic energy = `(K. - K)/(K) xx 100%` `= ((K.)/(K) - 1) xx 100% = (9/4 - 1) xx 100% = 125%`. |
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